how to solve modulus (2x - 1/x - 1)>2?
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Answered by
14
hello ....
(2x - 1) / (x - 1) 2
⇒ [2x (x + 1) - 1 (x + 1)] / (x2- 1) 2
⇒ (2x2+ 2x - x - 1) 2 (x2- 1)
⇒ 2x2+ x - 1 2x2- 2
⇒ x - 1
∴ Solution set =[ x ∈ R; x - 1 ]
= ( - 1 ,)
thank you ....
(2x - 1) / (x - 1) 2
⇒ [2x (x + 1) - 1 (x + 1)] / (x2- 1) 2
⇒ (2x2+ 2x - x - 1) 2 (x2- 1)
⇒ 2x2+ x - 1 2x2- 2
⇒ x - 1
∴ Solution set =[ x ∈ R; x - 1 ]
= ( - 1 ,)
thank you ....
Answered by
2
Answer:
donor refer the above
Step-by-step explanation:
it is quite bad
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