Math, asked by kavangcb, 11 months ago

how to solve n^2+n-552=0​

Answers

Answered by Anonymous
3

 {n}^{2}  + n - 552  = 0\\  {n}^{2}  + 24n - 23n - 552  = 0\\ n(n + 24) - 23(n + 24)  = 0\\ (n + 24)(n - 23) = 0 \\ n =  - 24 \: or \: n = 23

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Answered by ayushkumar777
1

Answer:

(n+24)(n-23)

Step-by-step explanation:

n^2+n-552=0

n^2+n(24-23)-552=0

n^2+24n-23n-552=0

n(n+24)-23(n+24)=0

(n+24)(n-23)=0

n+24=0

n= -24

n-23=0

n= 23

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