how to solve p(x)=2(x^2-3)-x
Answers
Answered by
1
Answer:
heya mate there's your answer
p(x)=2(x^2-3)-x
=2x^2-6-x
= 2x^2-x-6
=2x^2-4x+3x-6
=2x(x-2)+3(x-2)
=(x-2)(2x+3)
hope it helps you
Thank you
Answered by
2
Answer:
Sum of Zeroes is -1/2
product of zeros is -3
hope it's help uh
plz mark me as a brilliant
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