Question

how to solve pls give a written solution pls​

Answer 1

Answer:

The equivalent resistance is 6 Ω.

Step-by-step explanation:

According to the given diagram:

• $\sf{R_1}$ = 60 Ω
• $\sf{R_2}$ = 15 Ω
• $\sf{R_3}$ = 5 Ω
• $\sf{R_4}$ = 10 Ω

The resistors $\sf{R_2}$ and $\sf{R_3}$ are in series,

$\longrightarrow \: \sf{R_s} = R_2 + R_3$

$\longrightarrow \: \sf{R_s} = 15+ 5$

$\longrightarrow \: \sf{R_s} =20 \:ohms$

Replace the 15 Ω and 5 Ω with 20 Ω resistor.

__________________

The resistors $\sf{R_1}$, $\sf{R_{2,3}}$ and $\sf{R_4}$ are in parallel connection.

$\sf{\longrightarrow} \: \dfrac{1}{R_P} = \dfrac{1}{R_1} + \dfrac{1}{R_{2,3}} + \dfrac{1}{R_4}$

$\sf{\longrightarrow} \: \dfrac{1}{R_P} = \dfrac{1}{60} + \dfrac{1}{20} + \dfrac{1}{10}$

$\sf{\longrightarrow} \: \dfrac{1}{R_P} = \dfrac{1 + 3 + 6}{60}$

$\sf{\longrightarrow} \: \dfrac{1}{R_P} = \dfrac{10}{60}$

$\sf{\longrightarrow} \: \dfrac{1}{R_P} = \dfrac{1}{6}$

$\sf{\longrightarrow} \: R_P =6 \: ohms$

Equivalent Resistance = 6 Ω

Therefore, the equivalent resistance is 6 Ω.