how to solve plz help
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hope this helps you
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please do mark as brainliest
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Let one angle = x
Common difference is 20
Then...
Second angle = x + 20
And
Third angle = x + 20 + 20 = x + 40
Sum of all angles of a triangle is 180°
=> (x)° + (x + 20)° + (x + 40)° = 180°
=> 3x + 60 = 180
=> 3x = 180 - 60
=> 3x = 120
=> x = 120/3
=> x = 40
Smallest angle = 40°
Common difference is 20
Then...
Second angle = x + 20
And
Third angle = x + 20 + 20 = x + 40
Sum of all angles of a triangle is 180°
=> (x)° + (x + 20)° + (x + 40)° = 180°
=> 3x + 60 = 180
=> 3x = 180 - 60
=> 3x = 120
=> x = 120/3
=> x = 40
Smallest angle = 40°
aabhaji:
thnks
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