how to solve quadratic equation
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Answered by
4
To find the roots use the quadratic formula x = -b/2a +or- root of b2-4ac / 2a
for better idea refer....
for better idea refer....
Anonymous:
http://www.sosmath.com/algebra/quadraticeq/quadraformula/quadraformula.html
thanks
You're welcome induja
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Answered by
3
Let,ax^2+bx+c=0 be a quadratic equation.
d=b^2-4ac
then,
x=[-b+(d^1/2)]/2 or x=[-b-(d^1/2)]/2
x=[-b+(b^2-4ac)^1/2]/2 or x=[-b-(b^2-4ac)^1/2]/2
hence,by substituting a,b,c values,we get the absolute values of 'x'.
d=b^2-4ac
then,
x=[-b+(d^1/2)]/2 or x=[-b-(d^1/2)]/2
x=[-b+(b^2-4ac)^1/2]/2 or x=[-b-(b^2-4ac)^1/2]/2
hence,by substituting a,b,c values,we get the absolute values of 'x'.
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