how to solve que 8 and 7
Attachments:
Answers
Answered by
1
7. The 5th term of an A.P. =0. let the first term be a and common difference is d=> a+4d=0 => a= -4 d .
So 33rd term is a+32d => -4d+32d=28d and 12 th term is a+11d=> -4d+11d= 7d . As nth term of an A.P.is a+(n-1)d .
8. √8=2√2 and next term is √18=3√2 , √32=4√2 So common difference is √2 So next term is 5√2 and the term after 5√2 is 6√2 . Hence sum of next two terms is 11√2 .
So 33rd term is a+32d => -4d+32d=28d and 12 th term is a+11d=> -4d+11d= 7d . As nth term of an A.P.is a+(n-1)d .
8. √8=2√2 and next term is √18=3√2 , √32=4√2 So common difference is √2 So next term is 5√2 and the term after 5√2 is 6√2 . Hence sum of next two terms is 11√2 .
Similar questions