how to solve que in probability about neither nor either i get confuse
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Step-by-step explanation:
Suppose you have 3 blue balls, 5 red balls and 7 green balls.
Probability to select either a blue or a red = 5+3/15 = 8/15
Probability to select neither a blue nor a red = probability of green ball selection = 7/15
Neither case can also be viewed as: [1 - either case probability]
In either case you will have to add all the favorable outcomes of 'either cases'
Is this what you were looking for? If so, i hope it is almost clear. If not post a question and let us try to elucidate.
Anonymous:
If u aint busy, can you try a question?
ys of course
The sum of digits of a two digit number is 11. Find the probability that (a) the number is prime (b) the number is either divisible by 2 or 3.
The question was from brainly and it was easy too, i guess. Hope u've got the answer. Try this too. ''A card is drawn at random from a well shuffled pack of playing cards find the probability that the card drawn is neither a queen nor an Ace''. Good luck for the exam.
thnqqw againn
Happy MahaShivarathri!!
sm 2 u
Heya, how was your exam?
it ws osmmm
Kl to Maths he na? ATB
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