How to solve ques. no 34 and 35
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34 answer is 7.5 ohm
Sandeep03edu:
and 34th (a) part answer
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Hi sandeep...
Here's the answer for 35 th one...
Req is infinite....like even if you remove one parallel and one series connection it will not change...it will still be infinite...like if you take out a bucket of water from the ocean it will still be called the ocean....
So here is the solved part....
R1S (R2 P Req) =Req
R1 + R2 Req/ R2 + Req = Req
Taking LCM
R1R2 + R1Req = R2Req + R^2eq + R2Req
R1Req will get cancelled on both sides..
R^2eq - R1Req - R1R2 = 0..........u get a quadratic equation...
Solving it...
(Alfa,beta) = -b±√b^2 - 4ac/2a
Req= R1±√R1^2 + 4R1R2/2
Req= 1/2 (R1 + √ R1^2 + 4R1R2
If R1 = R2= R
Req= 1/2(R + √R2 + 4R)
Req= R/2(1+ √5)
Hope it helps ...
Cheers
Keep learning
BRAINLIEST ✌✌
Here's the answer for 35 th one...
Req is infinite....like even if you remove one parallel and one series connection it will not change...it will still be infinite...like if you take out a bucket of water from the ocean it will still be called the ocean....
So here is the solved part....
R1S (R2 P Req) =Req
R1 + R2 Req/ R2 + Req = Req
Taking LCM
R1R2 + R1Req = R2Req + R^2eq + R2Req
R1Req will get cancelled on both sides..
R^2eq - R1Req - R1R2 = 0..........u get a quadratic equation...
Solving it...
(Alfa,beta) = -b±√b^2 - 4ac/2a
Req= R1±√R1^2 + 4R1R2/2
Req= 1/2 (R1 + √ R1^2 + 4R1R2
If R1 = R2= R
Req= 1/2(R + √R2 + 4R)
Req= R/2(1+ √5)
Hope it helps ...
Cheers
Keep learning
BRAINLIEST ✌✌
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