how to solve question 21
plz tell me fast
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raj1167:
answer is 16 and 34
Answers
Answered by
1
xlet X be the breadth of the rectangle.
then length is x+18.
length and breadth is in increased by 6cm
then length is X+24 and breadth is x+6
given new area 336cm2
i. e (x+24)(x+6)=336
solving this gives the ans
then length is x+18.
length and breadth is in increased by 6cm
then length is X+24 and breadth is x+6
given new area 336cm2
i. e (x+24)(x+6)=336
solving this gives the ans
Answered by
1
Let the breadth be x.
So, length= x+18
Area of given rectangle= l×b= x(x+18)= x^2+18x
After increasing 6cm,
Breadth= x+6
Length= x+18+6= x+24
A.T.Q.
Area of new rectangle=x^2+18x+336
(x+6)(x+24)=x^2+18x+336
x^2+24x+6x+144=x^2+18x+336
x^2+30x+144=x^2+18x+336
x^2+30x-x^2-18x=336-144
12x=192
x=192/12
x=16cm
Ans=> Breadth=x=16cm
Length=x+18=16+18=34cm
So, length= x+18
Area of given rectangle= l×b= x(x+18)= x^2+18x
After increasing 6cm,
Breadth= x+6
Length= x+18+6= x+24
A.T.Q.
Area of new rectangle=x^2+18x+336
(x+6)(x+24)=x^2+18x+336
x^2+24x+6x+144=x^2+18x+336
x^2+30x+144=x^2+18x+336
x^2+30x-x^2-18x=336-144
12x=192
x=192/12
x=16cm
Ans=> Breadth=x=16cm
Length=x+18=16+18=34cm
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