How to solve question 4
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PA=PB=14cm (GIVEN)
AC=CE
BD=DE
(tangents from an external Point)
now,
Perimeter of triangle PCD=PC+CD+PD
=PC+CE+ED+PD
PC+AC+BD+PD
PA+PB=14+14=28
∴ Perimeter of ΔPCD= 28 cm
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