How to solve questions 30
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AB is parallel to DC
CBD=BDA(alternate angle)
Then 72°=72°
y=72°
x=4/3y
x=4/3*72
x=96°
Angle BAD=180-(72+96)
=180-168
=12°
Angle ABC=x+y
=72+96
=168°
Angle ABD=BDC
96°=96°
ANGLE BCD=180-(72+96)
=180-168
=12°
CBD=BDA(alternate angle)
Then 72°=72°
y=72°
x=4/3y
x=4/3*72
x=96°
Angle BAD=180-(72+96)
=180-168
=12°
Angle ABC=x+y
=72+96
=168°
Angle ABD=BDC
96°=96°
ANGLE BCD=180-(72+96)
=180-168
=12°
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