Question

How to solve questions like this?
2^{X-3} *3^{2x-8}=36

Answer 1

Answer:

x−3

×3

2x−8

=4×9

2

x−3

×3

2x−8

=2

2

×3

2

2

x−5

×3

2x−10

=1

x=5

as RHS is 1, the powers have to be zero on the LHS as anything raise to 0 is always 1

Thus x−5=0→x=5