Question

how to solve root 5 + root 3 divide by root5 -root 3

Answer 1

hiii!!

here's Ur answer..

$given \: \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \\ \\ = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } \\ \\ = \frac{( \sqrt{5} + \sqrt{3} )( \sqrt{5} + \sqrt{3}) }{( \sqrt{5} - \sqrt{3})( \sqrt{5} + \sqrt{3} ) } \\ \\ = \frac{ {( \sqrt{5} + \sqrt{3}) }^{2} }{ ({ \sqrt{5} )}^{2} - {( \sqrt{3} })^{2} } \\ \\ = \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} \times \sqrt{3} ) + {( \sqrt{3}) }^{2} }{5 - 3} \\ \\ = \frac{5 + 2 \sqrt{15} + 3}{2} \\ \\ = \frac{8 + 2 \sqrt{15} }{2}$

hope this helps..!!