how to solve sandwich theorem
Answers
Answer:
The sandwich theorem is also known as Squeeze theorem or Pinch theorem.
Step-by-step explanation:
In the above figure, we see Δ ABE, Δ ADF, Δ ADB and sector ADB.
Now, AB = AD (isosceles traingle)
Area (ΔABD) < Area (sector ADB) < Area (ΔADF)
1/2.AD.EB < x/2π.π.AD2 < 1/2.AD.DF
Cancelling the common terms from all sides, we get
EB < x.AD < DF
From Δ ABE, sinA = EB/AB, so EB = AB sinx (angle A= angle X)
Also, tanA = DF/AD, so DF = ADtanX
But AB = AD and
tanA = sinX/CosX
so, AD.sinA < x.AD < AD.sinA / cosA
= 1 < x / sinX < 1 / cosX
Taking reciprocals we get,
cosx < sinx / x < 1
Hence proved.
Using the above theorem we can easily prove some other trigonometric identities such as
limx->0sinx/x =1
limx->0 (1 – cosx)/x =0
We have to keep in mind some points while evaluating the limits.Suppose while evaluating a function where limx->af(x)/g(x) exists such that f(x) = 0 and G(x) = 0. Then in such cases, we rewrite f(x) and G(x) in such ways that we get 2 functions. This can be said as f(x) = f'(x).f”(x) such that f'(x) = 0.
Similarly we get g(x)=g'(x).g”(x) such that g'(x)=0. We then cancel out the common terms and we get the new limits as
limx->af(x) / g(x) = f'(a)/g'(a)