How to solve sec (-1110°)
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Answered by
3
sec is even fiunction
hence sec(-alp)=sec(alp)
sec(-1110)=sec(1110)
=sec(3(360)+30)
= sec(30)
=2/root(3)
hence sec(-alp)=sec(alp)
sec(-1110)=sec(1110)
=sec(3(360)+30)
= sec(30)
=2/root(3)
ritikadatta81:
What is alp?
i mean that is theta
Answered by
2
we know, sec(-x)=sec x
=>sec(-1110°)=sec(1110°)
=sec(3π+π/6)
=1/(cosine (3π+π/6)
=-1/(cosine(π/6))
=-1/(√3/2)
=-2/√3
=>sec(-1110°)=sec(1110°)
=sec(3π+π/6)
=1/(cosine (3π+π/6)
=-1/(cosine(π/6))
=-1/(√3/2)
=-2/√3
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