Question

How to solve sin 2Ф = 50/9

Answer 1

Answer:

Here, R=50cm=0.5mR=50cm=0.5m,

r=5cm=5×10−2m,x=50cm=0.5mr=5cm=5×10-2m,x=50cm=0.5m,

I1=3A,I2=2A,M=?I1=3A,I2=2A,M=?

M⋅=μ04π×2π2R2r2(R2+x2)3/2M⋅=μ04π×2π2R2r2(R2+x2)3/2

=10−7×2(3.14)2(0.5)2(5×10−2)2[0.2+0.52]3/2=10-7×2(3.14)2(0.5)2(5×10-2)2[0.2+0.52]3/2

M=3.48×10−9