how to solve sin(π/2-theta)?
Answers
Answered by
2
Explanation:
using appropriate
Addition formula
∙
sin
(
A
±
B
)
=
sin
A
cos
B
±
cos
A
sin
B
hence
sin
(
π
2
−
θ
)
=
sin
(
π
2
)
cos
θ
−
cos
(
π
2
)
sin
θ
now
sin
(
π
2
)
=
1
and
cos
(
π
2
)
=
0
hence
sin
(
π
2
)
cos
θ
−
cos
(
π
2
)
sin
θ
=
cos
θ
−
0
⇒
sin
(
π
2
−
θ
)
=
cos
θ
FOLLOW ME.......
Similar questions