Math, asked by sandhyamahilane2147, 11 months ago

How to solve sin 3A=cot(A-6) find A

Answers

Answered by edwardoswald29
0

Answer:a=24

Step-by-step explanation:

Cos= sin (90-a)------(1)

By using (1)

Sin 3a= cos(90-3a)

Therfore

Cos(90-3a)=cos(a-6)

90-3a=a-6

-4a=-96 cancel the minus

4a=96

A=96/4

A=24

Answered by rocky333
0

sin 3a = cos (a-6)

cos (90 - 3a ) = cos ( a - 6 )

90- 3a = a - 6

90+6 = a +3a

96=4a

a = 24

Similar questions