How to solve sin 5A+sin 3A/cos 5A+cos A=tan 4A
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sin 5 A + sin 3 A/cos 5A + cos3A
applying sinC+sinD formula in upper
2 sin 5+3/2 cos 5-3/2/2 cos 5+3/2 cos 5-3/2
2sin4A cos A/2cos 4A cosA
now 2cos 2A cancel from upper and lower we get
sin4A /cos4A
tan4A
applying sinC+sinD formula in upper
2 sin 5+3/2 cos 5-3/2/2 cos 5+3/2 cos 5-3/2
2sin4A cos A/2cos 4A cosA
now 2cos 2A cancel from upper and lower we get
sin4A /cos4A
tan4A
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