Question

How to solve sin15° ?​

Answer 1

Answer:

as per a formula in trigonometry

cos(90-x)= sin x

hence cos (90-15) = sin 15

cos (75) ≈ 0.259

Explanation:

same value can be found out by using natural sin table ...have a look at attached pic for reference

Sin 15° = 0.2588 or 0.259

Answer 2

Explanation:

sin15°= sin(45°-30°)

sin(A-B) = sinA cosB -cosA sinB

sin15°=sin45°cos30°-cos45°sin30°

sin15°=(1/√2×√3/2)-(1/√2×1/2)

sin15°=√3/2√2-1/2/√2

sin15°=(√3-1)/2√2