Question

how to solve square root of complex number

Answer 1

putting iota numbers values you can solve the square root of complex number

Answer 2

$\\ \sqrt{a ± bi} ^{ \neg} = \sqrt[2]{1} ^{\neg} ·( \sqrt{ \frac{a + \sqrt{ ({a}^{2} + {b}^{2} ) } }{2} } ±i \sqrt{ \frac{ - a + \sqrt{ ({a}^{2} + {b}^{2} )} }{2} } )$

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The symbol (√x' ) denotes the Real Valued square root of the complex number

or more specifically

Surd[x, 2]

Hence, Surd[1,2] = ²√1' = ±1