How to solve sum no 10 from the attachment below???
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Answer:
apply tan theta in both triangles ie P/b
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Answer:
let h=8.5
p=7.5
b= w1
then
= (8.5)^2 - ( 7.5 )^2
= 272. 25 - 56 125
= 16
then b^2 = 16
b =
= 4
so , w1 = 4 m
2nd
w2 = b
h = 8.5m
p = 4 m
then b^2 = h ^2 - p^2
= (8.5)^2 - 4^2
= 72.25 - 16
= 56.25
b =
b= 7.5
so , w2 = 7.5 m
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