Question

How to solve sum no 7 from the attachment given below using unitary method?

Answer 1

||✪✪ GIVEN ✪✪||

• 14 weavers can weave 210 sarees in 12 days.
• Now, have to weave 300 sarees in 10 days.
• How many Extra weavers Required ?

|| ★★ FORMULA USED ★★ ||

➺ If M1 men can do W1 work in D1 days working H1 hours per day and M2 men can do W2 work in D2 days working H2 hours per day, then

❦❦ (M1*D1*H1)/W1 = (M2*D2*H2)/W2 ❦❦

|| ✰✰ ANSWER ✰✰ ||

From Given Values we can say that, we have :-

→ M1 = 14

→ D1 = 12 days .

→ W1 = 210 sarees ( This is the work done Here.)

→ M2 = Let x .

→ D2 = 10 days.

→ W2 = 300 sarees.

Putting all values in Above Told Formula now, we get,

→ ( 14 * 12)/210 = ( x * 10) /300

Cross - Multiplying ,

→ 300 * 14 * 12 = x * 10 * 210

→ 4200 * 12 = x * 2100

Dividing both sides by 2100 now,

→ x = 24 .

So, Extra weavers Required = 24 - 14 = 10 weavers (Ans).

Hence, we need 10 more weavers to complete The given work in 10 days.

Answer 2

FORMULA USED :-

If M1 men can do W1 work in D1 days working H1 hours per day and M2 men can do W2 work in D2 days working H2 hours per day, then

(M1×D1×H1)/W1 = (M2×D2×H2)/W2

ANSWER :-

Given That :-

=> M1 = 14

=> M2 = x

=> W1 = 210 sarees (work done).

=> W2 = 300 sarees

=> D1 = 12 days.

=> D2 = 10 days.

Putting values :-

=> [ 14 * 12 ] /210 = [ x * 10 ] /300

Cross - Multiply

=> 300 * 14 * 12 = x * 10 * 210

=> 4200 * 12 = x * 2100

=> x = 24

Hence, Extra weavers Required = 24 - 14 = 10 weavers.