Question

How to solve sum no 8 from the attachment??? Ans-80 people

Answer 1

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It is given that , 280 Heads of People can complete The work in 10 days.

Also Given That, in 3 days These 280 heads of People completed Only (1/4)th of the Total work.

That Means we can say That :- (1 - 1/4) = (3/4)th of The work is Still Left to be done.

And, we have Days Left now = 10-3 = 7 days.

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Lets assume That, now we have X heads of People .

So, Now, with Work out Method we can say That :-

→ if 280 Workers complete (1/4)th of The work in 3 days Than how many workers will complete (3/4)th of the work in 7 days.

→ (M1 * D1 /W1) = (M2 * D2)/(W2)

Putting values now , we get :-

→ ( 280 * 3) / (1/4) = ( X * 7) /(3/4)

Cross - Multiply,

→ 280 * 3 * (3/4) = X * 7 * (1/4)

→ 280 * 9 = 7X

→ 7X = 280 * 9

Dividing by 7 both sides

→ X = 40*9

→ X = 360 Heads of People .

So,

→ Extra Heads of People Required = 360 - 280 = 80 Heads of People.

Hence, 80 More Heads of People Required To complete The work in Time.

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Answer 2

QUESTION:

A company has got the work of unloading goods from a ship in 10 days. 20 heads of people have been employed for this purpose. After three days it is seen that one fourth of the work has been completed. Let's workout using the method of the rule of three how many heads of the people a2b engaged to complete the work on time.

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CONCEPT USED:

Here, we are going to use the work out method,

The formula is:

$\mapsto\tt{\bigg(\dfrac{Men_1\times Day_1}{Work\:Done_1}\bigg)=\bigg(\dfrac{Men_2\times Day_2}{Work\:Done_2}\bigg)}$

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SOLUTION:

GIVEN:

• 280 PEOPLE COMPLETED ONE FOURTH OF THE WORK IN 3 DAYS.
• SO THREE FOURTH OF THE WORK IS LEFT WHICH IS EXPECTED TO BE COMPLETED IN 7 DAYS.

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TO FIND:

• HOW MANY MORE PEOPLE ARE TO BE ENGAGED TO COMPLETE THREE FOURTH OF THE LEFT WORK IN LEFT 7 DAYS.

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ANSWER:

[ Using the same formula we discussed above ]

$\mapsto\tt{\bigg(\dfrac{280\times 3}{\dfrac{1}{4}}\bigg)=\bigg(\dfrac{Men_2\times 7}{\dfrac{3}{4}}\bigg)}$

By cross multiplication,

$\mapsto\tt{\bigg(280\times 3\times \dfrac{3}{\cancel{4}}\bigg)=\bigg(Men_2\times 7\times \dfrac{1}{\cancel{4}}\bigg)}$

$\mapsto\tt{280\times 9 = 7 \times Men_2}$

$\mapsto\tt{Men_2=\bigg(\dfrac{280\times 9}{7}\bigg)}$

$\mapsto\tt{Men_2= 40 \times 9}$

$\mapsto\tt{Men_2= 360}$

Now, there were 280 people already.

So, more men required = 360 - 280 = 80 men.

Answer: 80 Men.

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