How to solve sum no 8 from the attachment using unitary method??? Ans-80people
Answers
Answer:
336 workers
Step-by-step explanation:
If there were 280 workers:
1/4 of the work = 3 days
Full work = 3 x 4 = 12 days
If there was 1 worker only:
280 workers = 12 days
1 worker = 280 x 12 =3360 days
Find the number of workers needed to complete the work in 10 days:
3360 days = 1 worker
1 day = 3360 workers
10 days = 3360 ÷ 10 = 336 workers
Answer: 336 workers
|| ✰✰ ANSWER ✰✰ ||
It is given that , 280 Heads of People can complete The work in 10 days.
Also Given That, in 3 days These 280 heads of People completed Only (1/4)th of the Total work.
That Means we can say That :- (1 - 1/4) = (3/4)th of The work is Still Left to be done.
And, we have Days Left now = 10-3 = 7 days.
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Lets assume That, now we have X heads of People .
So, Now, with Work out Method we can say That :-
→ if 280 Workers complete (1/4)th of The work in 3 days Than how many workers will complete (3/4)th of the work in 7 days.
→ (M1 * D1 /W1) = (M2 * D2)/(W2)
Putting values now , we get :-
→ ( 280 * 3) / (1/4) = ( X * 7) /(3/4)
Cross - Multiply,
→ 280 * 3 * (3/4) = X * 7 * (1/4)
→ 280 * 9 = 7X
→ 7X = 280 * 9
Dividing by 7 both sides
→ X = 40*9
→ X = 360 Heads of People .
So,
→ Extra Heads of People Required = 360 - 280 = 80 Heads of People.