Question

How to solve sum of additive inverse of two numbers like 4/9 and -2/3 please tell steps also and show all work​

Answer 1

$\sf number \: 1 = \frac{4}{9} \\ \sf \therefore Additive \: inverse = \frac{9}{4}$

$\sf number \: 2 = -\frac{2}{3} \\ \sf \therefore Additive \: inverse = -\frac{3}{2}$

$\sf sum \: of \: additive \: inverse \: of \: these \: numbers = \frac{9}{4} + \left( - \frac{3}{2} \right) \\ \\ \sf \rightarrow \quad \frac{9 - 6}{4} \\ \\ \sf \rightarrow \quad \frac{3}{4}$