Question

how to solve tan-1 2x/1-x2 + cot-1 1-x2/2x = pie/3

Answer 1

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Answer 2

Answer:

tan-1(2x\1-x^2)+tan -1(2x\1-x^2)=π\3

2tan-1(2x\1-x^2) =π\3

tan-1(2x\1-x^2) =π\6

(2x\1-x^2) =tan(π\6)

(2x\1-x^2) = 1\√3

2√3x = 1- x^2

X^2+ 2√3 - 1 =0

d= b^2 -4ac

12+4 =16

-b + or - √d\\2a

-2√3 + or - 4\\2

So by solving

We get two values for x ie.

X = -2 - √3

And x = 2- √3

Therefore , x= 2- √3