Math, asked by kj587068, 2 days ago

how to solve the. (90°-@)sin(90°-@)/sin@+cot 40°/tan 50°-(cos ×cos 20°+cos×cos70°)​

Answers

Answered by ankeshtiwari89
1

Answer:

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Step-by-step explanation:

Given expression : ((tanθcosθ)/sinθ) + cot(90°-50°)/tan50°

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