how to solve the ( a+2 ) ( a- 1)
Anonymous:
say!!
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Answered by
26
Hey user !!
So here's u r answer !!
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( a + 2 ) ( a - 1 ) = 0
By multiplying the brackets !
a ( a - 1 ) + 2 ( a - 1 ) = 0
a ^2 - a + ( 2 a - 2 ) = 0
a ^2 - a + 2 a - 2 = 0
a ^2 + a - 2 = 0
_______________________________________________
So here's u r answer !!
_________________________________________
( a + 2 ) ( a - 1 ) = 0
By multiplying the brackets !
a ( a - 1 ) + 2 ( a - 1 ) = 0
a ^2 - a + ( 2 a - 2 ) = 0
a ^2 - a + 2 a - 2 = 0
a ^2 + a - 2 = 0
_______________________________________________
Answered by
34
Hey..!! Here Is Your Ans..
(a + 2) (a - 1) [MULTIPLY BOTH BRACKETS]
#RS
HOPE THIS HELPS...☺☺
(a + 2) (a - 1) [MULTIPLY BOTH BRACKETS]
#RS
HOPE THIS HELPS...☺☺
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