Question

How to solve the differential equation (3x+2)^2 y'' + 5(3x+2)y' - 3y = x^2 + x + 1 ?

Answer 1

Answer:

THAT'2 YOUR NEWER \(_):

Explanation:

3v2, 4v5

Cube root of 2 = 4.2426

Quad root of 5 = 8.944

Now convert them in fraction

4.2426= 36

8.944 = 16

Put it in fraction and then divide...