Math, asked by rajeshrwt1480, 1 year ago

How to solve the following logarithm 2log5+3log4-4.log2

Answers

Answered by alberto17
3
2log5 + 3log4 - 4log2
= 2(0.6991) + 3log2² - 4(0.3010)
= 1.3982 + 6(0.3010) - 1.204
= 1.3982 + 1.806 - 1.204
= 2.0002

Thank you. Hope it helps.
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