Question

how to solve the given Quadratic equation. 1960x² -39.2x - 15.68 = 0 ​

Answer 1

Appropriate Question :

• how to solve the given Quadratic equation. 1960x² -39.2x - 15.68 = 0

Required Solution :

Given the following quadratic equation.

• => 1960x² - 39.2x - 15.68 = 0

The HCF of each coefficient and constant is 392. So divide both sides by 392, we get.

• => 5x² - 0.1x - 0.04 = 0

• To make calculation easier, we should not have the coefficient of x and the constant term in decimal. So Multiply both sides by 100.

• => 500x² - 10x - 4 = 0

Splitting the middle term, we get

• => 500x² - 50x + 40x - 4 = 0

• => 50x (10x - 1) + 4(10x - 1) = 0

• => (10x - 1)(50x + 4) = 0

✴ Case-1 ✴

• => 10x - 1 = 0
• => 10x = 1
• => x = 1/10

✴ Case-2 ✴

• => 50x + 4 = 0
• => 50x = -4
• => x = -4/50
• => x = -2/25

¶ Therefore ;

∆ Hence, x = 1/10, -2/25 ∆

Answer 2

SO L U T I O N :

Given the following quadratic equation.

=> 1960x² - 39.2x - 15.68 = 0

The HCF of each coefficient and constant is 392. So divide both sides by 392, we get.

=> 5x² - 0.1x - 0.04 = 0

To make calculation easier, we should not have the coefficient of x and the constant term in decimal. So Multiply both sides by 100.

=> 500x² - 10x - 4 = 0

Splitting the middle term, we get

=> 500x² - 50x + 40x - 4 = 0

=> 50x (10x - 1) + 4(10x - 1) = 0

=> (10x - 1)(50x + 4) = 0

✴ Case-1 ✴

=> 10x - 1 = 0

=> 10x = 1

=> x = 1/10

✴ Case-2 ✴

=> 50x + 4 = 0

=> 50x = -4

=> x = -4/50

=> x = -2/25

∆ Hence, x = 1/10, -2/25 ∆