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Let AB be x and BC be also x.
In the first half journey(A to B)...
Speed = 10 m/s
Distance = x
Time taken = Distance/Speed = x/10
In the final half journey (B to C).....
Speed = 15 m/s
Distance = x
Time taken = Distance/Speed = x/15
Total distance in the journey = x+x = 2x
Total time taken in the journey = x/10+x+15 = (3x+2x)/30 = 5x/30 = x/6
Average Speed = Total distance / Total time taken
= 2x/(x/6)
= 2x(6/x)
= 12 m/s.
So, the answer is (a) 12 m/s
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