How to solve the question Find the least number that is divided exactly by 15, 18 and 45 leaving a remainder of 5 in each case
Answers
Answered by
1
Hey!!!
We will basically find the LCM of these numbers and add 5 to them. Let's do this
By Prime Factorisation Method,
=> 15 = 3 x 5
=> 18 = 3² x 2
=> 45 = 3² x 5
Thus LCM = 3² x 2 x 5
=> LCM = 90
THUS Required answer = 90 + 5
=> 95
Hope this helps
We will basically find the LCM of these numbers and add 5 to them. Let's do this
By Prime Factorisation Method,
=> 15 = 3 x 5
=> 18 = 3² x 2
=> 45 = 3² x 5
Thus LCM = 3² x 2 x 5
=> LCM = 90
THUS Required answer = 90 + 5
=> 95
Hope this helps
Similar questions