Math, asked by maheshsutharr98, 9 months ago

how to solve the question
write the smallest number which is divisible by both 306 and 657
solve this and explain

Answers

Answered by mayankdas802
0

Answer:

We have to find LCM of 306 and 657.

Write given numbers into product of prime :

306 = 2×3²×17.

657 = 3² × 73.

LCM of 306 and 657.

= 2×3²×17×73.

= 22338.

Smallest number which is divisible by both 306 and 657 is 22338.

Step-by-step explanation:

Answered by IWantToScoreMuch
0

the smallest number which is divisible by both 306,657 is 3.

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