Math, asked by maheshsutharr98, 11 months ago

how to solve the question
write the smallest number which is divisible by both 306 and 657
solve this and explain

Answers

Answered by mayankdas802
0

Answer:

We have to find LCM of 306 and 657.

Write given numbers into product of prime :

306 = 2×3²×17.

657 = 3² × 73.

LCM of 306 and 657.

= 2×3²×17×73.

= 22338.

Smallest number which is divisible by both 306 and 657 is 22338.

Step-by-step explanation:

Answered by IWantToScoreMuch
0

the smallest number which is divisible by both 306,657 is 3.

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