Math, asked by Podilapu3368, 9 months ago

How to solve the simultaneous equation 3a + 2b=12 and 4a - b=5

Answers

Answered by arshiacraze
0

Step-by-step explanation:

By elimination method:

3a+2b=12

(4a-1b=5)*2

3a+2b=12----------(1)

8a-2b=10----------(2)

By adding the above equations:

[+2b and - 2b gets cancelled.]

11a=22

Therefore a=2

By substituting the value of a:

[From equation 1]

3*2+2b=12

12-6=2b

6=2b

b=3

.

Ans: a=2 and b=3

Hope it helps!

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