How to solve the simultaneous equation 3a + 2b=12 and 4a - b=5
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Step-by-step explanation:
By elimination method:
3a+2b=12
(4a-1b=5)*2
3a+2b=12----------(1)
8a-2b=10----------(2)
By adding the above equations:
[+2b and - 2b gets cancelled.]
11a=22
Therefore a=2
By substituting the value of a:
[From equation 1]
3*2+2b=12
12-6=2b
6=2b
b=3
.
Ans: a=2 and b=3
Hope it helps!
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