How to solve the square part in matrix?
Attachments:
Answers
Answered by
2
y2 - 5y = 6
y2 - 5y -6 =0
y2 -6y+y-6=0
y(y-6) +1(y-6)=0
y+1 = 0 or y-6=0
taking positive one
y= 6
y2 - 5y -6 =0
y2 -6y+y-6=0
y(y-6) +1(y-6)=0
y+1 = 0 or y-6=0
taking positive one
y= 6
Similar questions