How to solve the sum of four consecutive numbers is 32?
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Let the four consecutive number be >
◆ x
◆ x+1
◆ x+2
◆x+3
【Consecutive numbers have a difference of 1】
Given in question that their sum is 32.
So
x+(x+1)+(x+2)+(x+3)=32
4x+6=32
x=26÷4
x=6.5
So the numbers are
●6.5
●7.5
●8.5
●9.5
◆ x
◆ x+1
◆ x+2
◆x+3
【Consecutive numbers have a difference of 1】
Given in question that their sum is 32.
So
x+(x+1)+(x+2)+(x+3)=32
4x+6=32
x=26÷4
x=6.5
So the numbers are
●6.5
●7.5
●8.5
●9.5
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