Math, asked by Anonymous, 6 months ago

How to solve these types of questions....?
anyone can please explain this through an example....!!...
( I want an explanation through the beginning...!!!)
( wrong answers will be reported..!!)

Attachments:

Answers

Answered by creativevishnu4
3

Step-by-step explanation:

From fig,

sin A = x/c =>x = sinA * c

sin C = x/a => x - sin C * a

Now,

sin A * c = sin C *a

=> a/sin A = c/sin C.

similarly, we get that

a/sin A = b/sin B = c/ sin C

i.e., all their ratios are same and constant.

Hope it helps.

Please mark as brainliest.

Thank You

Answered by Anonymous
15

\sf{Refer\: above\: attachment}

THE MOST COMMON FORMULA THROUGH WHICH THIS EQUATION IS POSSIBLE :

SIN(θ) : - OPPOSITE/HYPOTENUSE

Attachments:
Similar questions