Question

How to Solve this?
10 less than twice a number is 0
Answer & Solve

Answer 1

Answer:

5

Step-by-step explanation:

Let's let the number be x

Twice the number would be 2x

10 less than the number would be 2x - 10

This would equal 0, 2x - 10 = 0

Now you can solve for x

2x - 10 = 0

[add +10 on both sides]

2x = 10

[divide 2 on both sides]

x = 10 ÷ 2

x = 5 #