How to solve this??
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Explanation:
Let voltage at the junction be V such that
V<10 V, V>5 V, V>6 V
Using Kirchhoff's law at the junction
Total incoming current = Total outgoing current
I = I(1) + I(2)
(10-V)/10 = (V-6)/20 + (V-5)/30
On solving we get V = 8 V
THEREFORE
I = (10-V)/10 = (10-8)/10 = 0.2 A
On further solving we get
I(1) = I(2) = 0.1 A
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