Question

How to solve this
21t²-t-2
we need to find zeroes by factorisation method

Answer 1

${21t}^{2} - t - 2 = 0 \\ {21t }^{2} - 7t + 6t - 2 = 0 \\ 7t(3t - 1) 2(3t - 1) = 0 \\ (7t + 2)(3t - 1) = 0 \\ t = - 2 \div 7 \ \: \\ t = 1 \div 3$
I hope it helps you!