how to solve this??
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Draw a base PQ as 5.8cm then from P construct or draw a 60degree angle using protractor or Compass, then from Q construct 30degree with protractor or compass(by bisecting 60degree angle for compass then extend and join both the lines) u will get a perfect drawing. Please mark me as the brainliest
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Figure in attachment...
- Draw a line segment PQ of 5.8cm.
- From point P, draw an arc with any radius and with that same radius, draw an arc from point x on the previous arc.
- draw line PR on intersecting arcs.
- From point Q, do same as shown in previous steps to get 60° angle.
- Now bisect the 60° angle and construct line through intersecting arcs to form line segment QR.
- ∆PQR is our required triangle.
hope it helps u mate....
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