Question

How to solve this? ∫31x2−16x−4

Answer 1

★Heya★

Integration of xⁿ dx = x(ⁿ+1)/( n + 1 )

And

integration of M dx = Mx

Where M € R

=>

Integration of (31x² - 16x - 4)dx is

31 x³ /3 -16 x² /2 - 4x + c

Where c is called constant of integration.

=>

31x³ /3 - 8x² - 4x + c