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Answered by
3
Heya!
Your answer :
Given : A, B , C are points on the sides OP , OQ and OR respectively such that AB||PQ , AC||PR
To prove : BC || QR
Proof : In triangle POQ , AB|| PQ
By Using BPT theorem
OA/AP = OB / BQ ......(1)
In triangle POR , AC || PR
By using BPT theorem
OA /AP = OC /CR.....(2)
from 1 and 2 equations
OB / BQ = OC / CR ...... (3)
By CBPT theorem
BC || QR
Hence proved.
Glad if helped!
Your answer :
Given : A, B , C are points on the sides OP , OQ and OR respectively such that AB||PQ , AC||PR
To prove : BC || QR
Proof : In triangle POQ , AB|| PQ
By Using BPT theorem
OA/AP = OB / BQ ......(1)
In triangle POR , AC || PR
By using BPT theorem
OA /AP = OC /CR.....(2)
from 1 and 2 equations
OB / BQ = OC / CR ...... (3)
By CBPT theorem
BC || QR
Hence proved.
Glad if helped!
Answered by
4
Heya !!
Here's your answer.. ⬇⬇
_____________________________
➡ Given :- A, B and C are points on OP, OQ and OR. AB || PQ and AC || PR.
➡ To Prove :- BC || QR
➡ Proof :- In ∆OPQ,
AB || PQ
OA/AP = OB/OQ --(1)
In ∆OPR,
AC || PR
OC/CR = OA/AP ---(2)
From eq. (1) and eq. (2) we get..
OB/OQ = OC/CR
BC divides ∆OQR,
Hence, by CPCT it is proved that
BC || PR.
__________________________
Hope it helps..
Thanks :)
Here's your answer.. ⬇⬇
_____________________________
➡ Given :- A, B and C are points on OP, OQ and OR. AB || PQ and AC || PR.
➡ To Prove :- BC || QR
➡ Proof :- In ∆OPQ,
AB || PQ
OA/AP = OB/OQ --(1)
In ∆OPR,
AC || PR
OC/CR = OA/AP ---(2)
From eq. (1) and eq. (2) we get..
OB/OQ = OC/CR
BC divides ∆OQR,
Hence, by CPCT it is proved that
BC || PR.
__________________________
Hope it helps..
Thanks :)
neosingh:
BPT and thales theorem is same right?
yes
okay, thanks for confirming. Laydon u realise all the 3 ques were kinda same.
welcome @neosingh
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