Question

how to solve this?????????

Answer 1

fedc is a squar .to ed=fc and cd=de

sin30=ac/ab=ac/100
1/2=ac/100;. ac=50.

af=ac-fc=50-10=40

again,. tan60=af/fe=40/fe
√3=40/fe;. fe =40/√3 ×√3/√3
fe=40√3/3
fe=cd=40√3/3
is your answer
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