Question

how to solve this ( 5x-7) (7x+1)=(7x-5) (2x+1)?​

Answer 1

Step-by-step explanation:

35x-6 = 14x - 4

35x-14x= -4+6

59x=2

x=2/59

Answer 2

Step-by-step explanation:

There are a certain sequence of steps you need to know about, but do not really need to follow them in the exam.

First, Binomial Algebraic Multiplication

You need to multiply each term of multiplicand with each term of multiplier one at a time.

For example,

$(5x - 7)(7x + 1) = (5x \times 7x) + (5x \times 1) + ( - 7 \times 7x) + ( - 7 \times 1)$

$= 35 {x}^{2} + 5x - 49x - 7 \\ = 35x {}^{2} - 44x - 7$

Similarly, for the RHS,

$(7x - 5)(2x + 1) = 14x {}^{2} - 3x - 5$

Thus, we can say,

$35 {x}^{2} - 44x - 7 = 14 {x}^{2} - 3x - 5 \\ = > 35 {x}^{2} - 14 {x}^{2} - 44x + 3x = 7 - 5 \\ = > 21 {x}^{2} - 41x = 2$

Please review the question. It is incorrect.