Question

How to solve this..?

Answer 1

Answer:

Step-by-step explanation:

Its quite easy first u find BC as OC and OD r raidii and O = 90

Like wise find AC

ACB is also 90 as angle in semi circle

Find Ar of semicircle and subtract Ar of triangle from it

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ANSWER IS D PART 112

Answer 2

Here is your answer...
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ACBOA is a semicircle with diameter 28 cm.
Radius = 14 cm
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Area of semicircle =
$\frac{1}{2} \pi {r}^{2}$
.
$\frac{1}{2} \times \frac{22}{7} \times 14 \times 14$
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$308 {cm}^{2}$
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Now in triangle ABC, AO = CO= radius.
Therefore CO = 14cm.
Now CO is perpendicular to AB.
Area Of triangle ABC =
$\frac{1}{2} \times base \times height$
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$\frac{1}{2} \times 28 \times 14 \\ = 196 {cm}^{2}$
.
Now area of ruled region
= area of semicircle - area of triangle
= 308cm² - 196cm²
=112cm²
.
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ANS. = 112cm²
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I Hope This Will Help You