How to solve this? Can anyone help?
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Answer:
3*4/2
EF*height
Step-by-step explanation:
Hope it helps you
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(a) Here,
the base of ABC,b=4cm
the height of ABC,h=3cm
We know,
ABC triangle's area=(b*h)/2
=(4*3)/2
=6cm^2
Ans.6 square centimeters.
(b) Here,
the base of DEF,b'=4cm
the height of DEF,h'=3cm
We know,
DEF triangle's area=(b'*h')/2
=(4*3)/2
=6cm^2
Ans.6 square centimeters.
(c) Here,
the base of PQR,b"=4cm
the height of PQR,h"=3cm
We know,
PQR triangle's area=(b"*h")/2
=(4*3)/2
=6cm^2
Ans.6 square centimeters.
Hope this will help you.
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